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CGP EDU Academic Team
Published on: September 12, 2026
A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is $0.6 g cm^{-3}$ . The mass of block is
Text Solution
Verified by ExpertsThe correct answer is:
C
Weight of block
= Weight of displaced oil + Weight of displaced water
⇒ ⇒ $mg = V_{1} \rho_{0} g + V_{2} \rho_{W} g$
⇒ ⇒ $m = (10 \times 10 \times 6) \times 0.6 + (10 \times 10 \times 4) \times 1$ = 760 gm.
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